Password Entropy, Part II
Passwords are expensive to crack
Even assuming a centralized effort could be an order of magnitude more efficient, this still leaves us with an estimate of US$1M to perform a 2⁷⁰ SHA256 evaluations and around US$1B for 2⁸⁰ evaluations^{1}.
So it would cost $1M to crack a 71bitsofentropy password (on average..), and $1B to crack an 81bit password.
Pattern  bits of entropy  cost to crack 

MotocrossVarietyGaveScroll  
= 4·log_{2}(6^{5})  51.70 bits  <$1M 
MotocrossVarietyGaveScrollFilter  
= 5·log_{2}(6^{5})  64.62 bits  <$1M 
MotocrossVarietyGaveScrollFilterUncombed  
= 6·log_{2}(6^{5})  77.55 bits  $1M  $1B 
and the nondiceware passwords:
Pattern  equation  bits of entropy  cost to crack 

1234567890  log_{2}(10,000,000,000)  33.22 bits  probably a buck 
wCEHMbIs  6·8  48 bits  could probably do it on an iPad 
abcdefghijklm  13·log_{2}(26)  61.11 bits  <$1M 
H65j/aS5vfmm  9·8  72 bits  $1M 
0mE07rdje4xzvxUE  12·8  96 bits  more than $1B 
aT7bubJTM4w2RoyeNPsQ  15·8  120 bits  way more than $1B 
Now this is all Assuming lots of things, like:

the hash algorithm is SHA256, and not SHA224 or SHA512 or SHA3 or scrypt

we’re just doing one round (I think), not sha256(..sha256(x)..)

we can ignore all(?) of the known attacks on SHA256, like collision attacks (finding the collision would be even harder?), length extension attacks (again, harder?), attacks we don’t even know about…

the source is right
They provide a source paper^{2} that goes into depth:
In 2013, Bitcoin miners collectively performed ≈ 2^{75} SHA256 hashes in exchange for bitcoin rewards worth ≈ US$257M. … Even assuming a centralized effort could be an order of magnitude more efficient, this still leaves us with an estimate of US$1M to perform a 2^{70} SHA256 evaluations and around US$1B for 2^{80} evaluations.